A solid metallic cube of side 4.4 cm is melted and recast in the form of a wire of radius 2 mm. Find the length (in cm) of the wire. (Use $π = \frac{22}{7}$)
Answer & explanation
Correct answer: option 3
We know that,
Volume of cube = a3
Volume of cylinder = πr2h
Given,
Length of the edge, a = 4.4 cm
Radius = 2 mm = 0.2 cm
So,
Volume of the cube = (4.4)3 = 85.184 cm3
Now, Volume of the wire = πr2h
\(\frac{22}{7}\)× 0.22 = \(\frac{0.88}{7}\)
We know that, Volume of the cube = volume of the wire
So, Length of the wire = \(\frac{a^3}{ πr^2h }\)
\(\frac{85.184 × 7}{0.88}\) = \(\frac{596.288}{0.88 }\) = 677.6