Target Exam

CUET

Subject

General Aptitude Test

Chapter

Quantitative Reasoning

Topic

Mensuration: 2D/3D

Question:

Match List-I with List-II

List-I (Figures, etc.)

List-II (Area/Volume/Diagonal etc.)

(A) Surface area of Cube

(I) $π(R^2 – r^2)$

(B) Volume of Right pyramid

(II) $a\sqrt{2}$

(C) Area of Circular Ring

(III) $6a^2$

(D) Diagonal of Square

(IV) $\frac{1}{3}$ (area of base) × height

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Correct Answer:

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Explanation:

The correct answer is Option (3) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

List-I (Figures, etc.)

List-II (Area/Volume/Diagonal etc.)

(A) Surface area of Cube

(III) $6a^2$

(B) Volume of Right pyramid

(IV) $\frac{1}{3}$ (area of base) × height

(C) Area of Circular Ring

(I) $π(R^2 – r^2)$

(D) Diagonal of Square

(II) $a\sqrt{2}$

(A) Surface area of Cube: A cube has 6 faces, each being a square with area $a^2$. Therefore, the total surface area is $6a^2$.

Matches with (III)

(B) Volume of Right pyramid: The volume of any pyramid is defined as one-third of the product of its base area and its perpendicular height.

Matches with (IV)

(C) Area of Circular Ring: A ring is the area between two concentric circles. It is calculated by subtracting the area of the inner circle ($\pi r^2$) from the outer circle ($\pi R^2$), which gives $\pi(R^2 - r^2)$.

Matches with (I)

(D) Diagonal of Square: Using the Pythagorean theorem ($a^2 + a^2 = d^2$), the diagonal of a square with side $a$ is $\sqrt{2a^2}$, which simplifies to $a\sqrt{2}$.

Matches with (II)