The price of an article was increased by x%, later the new price was decreased by x%. If the latest price was Rs.1, then the original price was?

Rs.\(\frac{10000}{10000-x^2}\)

Original price  × [ \(\frac{100+x}{100}\) ] ×[ \(\frac{100-x}{100}\) ] = 1

original price  × \(\frac{(100+x) × ( 100-x) }{10000}\) = 1

original price ×  (10000-x²) = 10000             

∴ [(a+b) (a-b)] = a² - b²]

original price = \(\frac{10000}{10000-x^2}\)