The price of an article was increased by x%, later the new price was decreased by x%. If the latest price was Rs.1, then the original price was? |
Rs 1 Rs.\(\frac{1-x^2}{100}\) Rs.\(\frac{1000}{1000-x^2}\) Rs.\(\frac{10000}{10000-x^2}\) |
Rs.\(\frac{10000}{10000-x^2}\) |
Original price × [ \(\frac{100+x}{100}\) ] ×[ \(\frac{100-x}{100}\) ] = 1 original price × \(\frac{(100+x) × ( 100-x) }{10000}\) = 1 original price × (10000-x2) = 10000 ∴ [(a+b) (a-b)] = a2 - b2] original price = \(\frac{10000}{10000-x^2}\) |