In the nuclear decay given below, the particles emitted in the sequence are:

$β,α,γ$

The correct answer is Option (4) → $β,α,γ$

Given nuclear decay sequence:

$Z^A P \;\;\longrightarrow\;\; Z+1^A Q \;\;\longrightarrow\;\; Z-1^{A-4} R \;\;\longrightarrow\;\; Z-1^{A-4} R^*$

Analysis:

1. $Z^A P \;\;\to\;\; Z+1^A Q$ Here, $Z$ increases by 1, $A$ unchanged → β⁻ emission.

2. $Z+1^A Q \;\;\to\;\; Z-1^{A-4} R$ Here, $Z$ decreases by 2, $A$ decreases by 4 → α emission.

3. $Z-1^{A-4} R \;\;\to\;\; Z-1^{A-4} R^*$ Here, same $Z$ and $A$, only energy state changes → γ emission.

✔ Sequence of emitted particles: β⁻, α, γ