The peak voltage through a capacitive circuit is of 25 V. Calculate the current in the circuit if the capacitance is 15 microfarads and the voltage changes 50 times in a second.

2.6 A 1.7 x 103 A 2.6 x 103 A 1.7 A

2.6 x 103 A

v = 50/sec w = 2πv = 2 x π x 50 = 630 rad/sec C = 15 microfarads = 15 x 10-6 F V = 25 V  I = 25/[630 rad/sec x 15 x 10-6 F] = 2.6 x 103 A