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The radius of the arc BD representing a wire is 60 cm. The magnitude of the magnetic field produced at centre C, if a current of 3.0 A flows in the wire, will be
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$\frac{5\pi}{6} × 10^{-7}T$ $\frac{5\pi}{12} × 10^{-7}T$ $\frac{5}{6} × 10^{-7}T$ $\frac{\pi}{6} × 10^{-7}T$ |
$\frac{5\pi}{6} × 10^{-7}T$ |
The correct answer is Option (1) → $\frac{5\pi}{6} × 10^{-7}T$ |
