CUET Preparation Today
If $A=\begin{bmatrix}1 & 1 & -2\\2 & 1 & -3\\5 & 4 & -9 \end{bmatrix}$, then |A| is equal to |
0 1 -1 2 |
0 |
The correct answer is Option (1) → 0 $A=\begin{bmatrix}1 & 1 & -2\\2 & 1 & -3\\5 & 4 & -9 \end{bmatrix}$ $C_3→C_3+C_1+C_2$ $|A|=\begin{bmatrix}1 & 1 & 0\\2 & 1 & 0\\5 & 4 & 0\end{bmatrix}$ $⇒|A|=0$ |
