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-- Mathematics - Section B2
Calculus
If $x=2t^3+3, y=3t^2+6t+5, $ then the value of $\frac{d^2y}{dx^2}$ is :
$-\frac{3}{t}$
$-\frac{3}{8t^3}$
$-\frac{4}{7t^2}$
$\frac{6t+6}{4t}$