The graph shows the variation of the magnification (m) produced by a thin lens with image distance (v). The focal length of the lens is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{b}{c}$
Magnification of a lens is,
$m=\frac{v}{u}$
and,
using len's maker formula,
$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$
Multiplying this by 'v'
$\frac{v}{f}=1-m$
and,
$v_1$, image distance from lens = $+a$
$⇒m_1=1-\frac{a}{f}$
$v_2$, image distance from lens = $a+b$
$m_2=1-\frac{a+b}{f}$
$⇒m_2-m_1=c=\frac{b}{f}$
$⇒f=\frac{b}{c}$