The ratio of peak to peak value and r.m.s value of an alternating current is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 2√2
For a sinusoidal alternating current \( I = I_0\sin\omega t \), the peak-to-peak value is measured from the negative crest \( -I_0 \) to the positive crest \( +I_0 \), and the r.m.s. value is the peak value divided by \( \sqrt{2} \).
\( I_{\mathrm{pp}} = 2I_0 \)
\( \displaystyle I_{\mathrm{rms}} = \frac{I_0}{\sqrt{2}} \)
\( \displaystyle \frac{I_{\mathrm{pp}}}{I_{\mathrm{rms}}} = \frac{2I_0}{I_0/\sqrt{2}} \)
\( \displaystyle \frac{I_{\mathrm{pp}}}{I_{\mathrm{rms}}} = 2\sqrt{2} \)