A bag contains 3 white, 4 black and 2 red balls. If 2 balls are drawn at random (without replacement), then the probability that both the balls are white is :

$\frac{1}{12}$

The correct answer is Option (3) → $\frac{1}{12}$

Total balls → 9

no. of white balls → 3

black balls → 4

red balls → 2

probability of 2 drawn of balls to be white

$⇒\frac{{^3C}_2}{{^9C}_2}=\frac{3×2}{9×8}=\frac{1}{12}$