In \( \beta^{-} \) decay, an electron is emitted. It originates from
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → decay of a neutron from the nucleus
There are no free electrons inside a nucleus. In \( \beta^{-} \) decay a neutron inside the nucleus changes into a proton, and the electron (with an antineutrino) is created in that process and emitted.
\( \displaystyle n \rightarrow p + e^{-} + \bar{\nu} \)
The proton stays in the nucleus, so Z increases by 1 while A is unchanged.
Note: This question is from the pre-rationalised NCERT book (2022-23). The topic was removed from the latest NCERT book (2026-27), and it also appears to be out of the CUET 2026 syllabus.
NCERT (Pre-rationalised edition, 2022-23):
Beta Decay – “… In beta-minus decay, a neutron transforms into a proton within the nucleus according to
\( \displaystyle n \rightarrow p + e^{-} + \bar{\nu} \qquad (13.24) \)
whereas in beta-plus decay, a proton transforms into neutron (inside the nucleus) via
\( \displaystyle p \rightarrow n + e^{+} + \nu \qquad (13.25) \)
These processes show why the mass number \( A \) of a nuclide undergoing beta decay does not change; one of its constituent nucleons simply changes its character according to Eq. (13.24) or (13.25).”