If the magnitude of the vector \(3\hat{\imath}+\lambda\hat{\jmath}+6\hat{k}\) is 7, then the values of \(\lambda\) are
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \(\pm 2\)
The magnitude of \(x\hat{\imath}+y\hat{\jmath}+z\hat{k}\) is \(\sqrt{x^2+y^2+z^2}\):
\(\sqrt{9+\lambda^2+36} = 7\)
\(45+\lambda^2 = 49\)
\(\lambda^2 = 4\)
\(\lambda = \pm 2\)