Practicing Success
Practicing Success
CUET Preparation Today
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a b c d |
a |
$ B = \frac{\mu_0 I R^2}{2(R^2+x^2)^\frac{3}{2}} $ $\Rightarrow 54\mu T = \frac{\mu_0 I 3^2}{2(3^2+4^2)^\frac{3}{2}} = \frac{9\mu_0 I}{250}$ $\Rightarrow \mu_0I = 1500$ $ \text{Magnetic field at centre of loop }B_c = \frac{\mu_0 I}{2R} = \frac{\mu_0 I}{6} = 250\mu T$ |
