$f(x)=x^3+p x^2+q x+10$ has a maximum at

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Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

$f(x)=x^3+p x^2+q x+10$ has a maximum at x = -3 and a minimum at x = 1. The values of p and q are:

Options:

p = -3, q = -9

p = 3, q = 9

p = -3, q = 9

p = 3, q = -9

Correct Answer:

p = 3, q = -9

Explanation:

The correct answer is Option (4) → p = 3, q = -9