Practicing Success
If x3 - 4x2 + 19 = 6(x-1) find \(\left[ {x}^{2} + \frac{1}{x-4}\right]\) |
2 4 6 8 |
6 |
x3 - 4x2 + 19 = 6(x-1) x2 (x -4) + 19 = 6(x-1) Divide by (x-4) ⇒ x2 + \(\frac{19}{x-4}\) = \(\frac{6(x-1)}{x-4}\) ⇒ x2 + \(\frac{1}{x-4}\) + \(\frac{18}{x-4}\) = \(\frac{6(x-1)}{x-4}\) ⇒ x2 + \(\frac{1}{x-4}\) = \(\frac{6(x-1)}{x-4}\) - \(\frac{18}{x-4}\) ⇒ \(\left(x^2 + \frac{1}{x-4}\right)\) = \(\frac{6x-6-18}{x-4}\) = \(\frac{6(x-4)}{(x-4)}\) ⇒ \(\left(x^2 + \frac{1}{x-4}\right)\) = 6 |