Seven children A, B, C, D, E, F and G are standing in a line. G is to the right of D and to the left of B. A is to the immediate right of C. A and D have one child between them. E and B have two children between them. D and F have two children between them.
Who is on the extreme right?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → F
Number the places 1 to 7 from the left. C and A stand together as C A, and D must be two places from A, so D is either two places to the right of A or two places to the left of A. Each case is tried with the other clues.
D two places to the left of A (D C A):
G and B must both stand to the right of D, but the two places after D are taken by C and A
D at 1 (F at 4): places 5, 6, 7 are left for G, B and E, and no order keeps two children between E and B
D at 2 (F at 5): G and B take 6 and 7, so E is 1st, far more than two places from B
D at 3 (F at 6): G and B must take places 6 and 7, but place 6 is F’s
D at 4: only place 7 is left after A for both G and B, so this case fails
D two places to the right of A (C A _ D):
G and B need two places to the right of D, so D is at 4 or 5
D at 5 puts C at 2, and F would have to be 3 places from D, at 2 or 8: impossible
So C is 1st, A 2nd, D 4th, and F (3 places from D) is 7th
G and B take places 5 and 6 (G left of B), and E takes place 3, with two children (D, G) between E and B
