Three unbiased coins are tossed. What is the probability of getting at least 2 heads?

$\frac{1}{2}$

The correct answer is Option (3) → $\frac{1}{2}$

Total number of outcomes when 3 unbiased coins are tossed:

$2^3 = 8$

Sample space:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Favorable outcomes for "at least 2 heads":

• HHH
• HHT
• HTH
• THH

Number of favorable outcomes = 4

Required probability:

$\frac{4}{8} = \frac{1}{2}$