Three unbiased coins are tossed. What is the probability of getting at least 2 heads?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{1}{2}$
Total number of outcomes when 3 unbiased coins are tossed:
$2^3 = 8$
Sample space:
{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
Favorable outcomes for "at least 2 heads":
- HHH
- HHT
- HTH
- THH
Number of favorable outcomes = 4
Required probability:
$\frac{4}{8} = \frac{1}{2}$