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CUET
Physics
Dual Nature of Radiation and Matter
a
b
c
d
$ \frac{1}{2} mv^2 = \frac{hc}{\lambda} - \phi$
$ \frac{1}{2} mv'^2 = \frac{4hc}{3\lambda} - \phi = \frac{4}{3} \frac{hc}{\lambda} - \phi = \frac{4}{3} (\frac{1}{2}( mv^2 + \phi) $
$ v'> v \sqrt{\frac{4}{3}}$