Variation of particle momentum and the associated de-Broglie wavelength is represented by
Answer & explanation
Correct answer: option 3
The correct answer is Option (3).
According to De-Broglie wavelength, λ
$P=\frac{hc}{λ}⇒h∝\frac{1}{λ}$
Variation of particle momentum and the associated de-Broglie wavelength is represented by
Correct answer: option 3
The correct answer is Option (3).
According to De-Broglie wavelength, λ
$P=\frac{hc}{λ}⇒h∝\frac{1}{λ}$