In an A.P. if mth term is n and the nth term is m, where m ≠ n, find the pth term. |
$n+m+p$ $m-p$ $n+m-1$ $n+m-p$ |
$n+m-p$ |
The correct answer is Option (4) → $n+m-p$ Let the A.P. have first term a and common difference d. Given: $T_m = a + (m-1)d = n \quad (1)$ $T_n = a + (n-1)d = m \quad (2)$ Subtract (1) from (2): $(n-m)d = m - n \Rightarrow d = -1$ Substitute $d=-1$ into (1): $a + (m-1)(-1) = n \Rightarrow a - m + 1 = n \Rightarrow a = n + m – 1$ Now, the pth term: $T_p = a + (p-1)d$ $= (n + m - 1) + (p-1)(-1)$ $=n+m−p$ |