What is the Highest Common Factor of $\frac{7}{16},\frac{21}{32}$ and $\frac{49}{8}$?
Answer & explanation
Correct answer: option 4
HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)
The given fractions are : $\frac{7}{16},\frac{21}{32}$ and $\frac{49}{8}$.
LCM of 16, 32, 8 = 32
HCF of 7, 21, 49 = 7
The HCF of $\frac{7}{16},\frac{21}{32}$ and $\frac{49}{8}$ = \(\frac{7}{32}\)