What is the average of the first six prime numbers?

6 $6\frac{5}{6}$ $9\frac{1}{3}$ 7

$6\frac{5}{6}$

1st 6 prime numbers are 2, 3, 5, 7, 11,13 Average = \(\frac{41}{6}\) = 6 \(\frac{5}{6}\)