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CUET
General Test
Quantitative Reasoning
Algebra
Simplify the following.
$81^{\frac{3}{4}}+[(20 ÷ 5\, of\, 3 × 6) + {(8 ÷ 24\, of\, 3) × 4} − 10 ÷ 5] − (\frac{1}{32})^{-\frac{2}{5}}$
$24\frac{1}{4}$
$21\frac{1}{9}$
$27\frac{4}{5}$
$29\frac{4}{9}$