Area bounded by the curve $y=x^3$, the x-axis and the abscissa $x=-2$ and $x=3$ is :
Answer & explanation
Correct answer: option 1
The correct answer is option (1) → $\frac{97}{4}$
area required = $=-\int\limits_{-2}^0x^3dx+\int\limits_0^3x^3dx$
$=\left[-\frac{x^4}{4}\right]_{-2}^0+\left[\frac{x^4}{4}\right]_0^3$
$=\frac{16+81}{4}=\frac{97}{4}$