If $(0.4x+\frac{1}{x}) = 5$, what is the value of $(0.064x^3+\frac{1}{x^3})$?
Answer & explanation
Correct answer: option 3
If x + \(\frac{1}{x}\) = n
then, $x^3 +\frac{1}{x^3}$ = n3 - 3 × n
If $(0.4x+\frac{1}{x}) = 5$
then, $(0.064x^3+\frac{1}{x^3})$ = 53 - 3 × 0.4 × 5
$(0.064x^3+\frac{1}{x^3})$ = 125 - 6 = 119