CUET Preparation Today
The longest wavelength in Balmar Series of hydrogen spectrum will be: |
1216 Å 5600 Å 4800 Å 6563 Å |
6563 Å |
The correct answer is Option (4) → 6563 Å According to Rydberg formula, $\frac{1}{λ}=R_H\left(\frac{1}{{n_f}^2}-\frac{1}{{n_i}^2}\right)$ $n_f=2,n_i=3$ $\frac{1}{λ}=R_H\left(\frac{1}{4}-\frac{1}{9}\right)$ $⇒λ=6563 Å$ |
