Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Relations and Functions

Question:

If $f(x)=\sin^2 x + \sin^2(x +\frac{π}{3}) + \cos(x +\frac{π}{2})\cos x$ and $g (5/4) =1$, then $gof (x)$, is

Options:

a polynomial of first degree in sin x and cos x

a constant function

a polynomial of second degree in sin x and cos x

none of these

Correct Answer:

a constant function

Explanation:

We have,

$f(x)=\sin^2 x + \sin^2(x +\frac{π}{3}) + \cos(x +\frac{π}{2})\cos x$

$⇒f(x)=\frac{1}{2}\left.\begin{matrix}1-\cos 2x+1-\cos(2x+\frac{2π}{3})+\cos(2x+\frac{π}{3})+\frac{π}{3}\cos\end{matrix}\right\}$

$⇒f(x)=\frac{1}{2}\left[\frac{5}{2}-\left.\begin{matrix}\cos 2x+\cos(2x+\frac{2π}{3})\end{matrix}\right\}+\cos(2x+\frac{π}{3})\right]$

$⇒f(x)=\frac{1}{2}\left[\frac{5}{2}-2\cos(2x+\frac{π}{3})\cos\frac{π}{3}+\cos(2x+\frac{π}{3})\right]$

$⇒f(x)=\frac{5}{4}$ for all $x ∈ R$.

$∴gof(x)=g(f(x))=g(\frac{5}{4})=1$ for all x.

Hence, $gof (x)$ is a constant function.