Match List I with List II
| LIST I | LIST II | ||
| A. | $3^3≡b(mod\, 9)$ | I. | 4 |
| B. | $2^5≡b(mod\, 15)$ | II. | 0 |
| C. | $4^3≡b(mod\, 10)$ | III. | 2 |
| D. | $5^3≡b(mod\, 12)$ | IV. | 5 |
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → A-II, B-III,C-I,D-IV
(A) $3^3≡b(mod\, 9)$ = remainder $\left(\frac{3^3}{9}\right)=0$ (II)
(B) $2^5≡b(mod\, 15)$ = $r(\frac{25}{15})=2$ (III)
(C) $4^3≡b(mod\, 10)$ = $r(\frac{64}{10})=4$ (I)
(D) $5^3≡b(mod\, 12)$ = $r(\frac{5^3}{12})=5$ (II)