Integrating factor of $\frac{d y}{d x}+\frac{y}{x}=x^3-3$; (x > 0) is :
Answer & explanation
Correct answer: option 1
I.F. $=e^{\int \frac{1}{x} d x}=e^{\log x}=x$
Hence (1) is the correct answer.
Integrating factor of $\frac{d y}{d x}+\frac{y}{x}=x^3-3$; (x > 0) is :
Correct answer: option 1
I.F. $=e^{\int \frac{1}{x} d x}=e^{\log x}=x$
Hence (1) is the correct answer.