In $\triangle ABC$, which of the following is not true is: A. $\vec{AB}+\vec{BC}+\vec{CA}=\vec{0}$ Choose the correct answer from the options given below: |
E and B only A and C only C only B and C only |
C only |
The correct answer is Option (3) → C and E only $\overrightarrow{AB}+\overrightarrow{BC}=\overrightarrow{AC}.$ $\overrightarrow{CA}=-\overrightarrow{AC},\; \overrightarrow{CB}=-\overrightarrow{BC},\; \overrightarrow{BA}=-\overrightarrow{AB}.$ $(A)\;\overrightarrow{AB}+\overrightarrow{BC}+\overrightarrow{CA} =\overrightarrow{AC}-\overrightarrow{AC}=\vec{0}\;\text{True}.$ $(B)\;\overrightarrow{AB}+\overrightarrow{BC}-\overrightarrow{AC} =\vec{0}\;\text{True}.$ $(C)\;\overrightarrow{AB}+\overrightarrow{BC}-\overrightarrow{CA} =\overrightarrow{AC}+\overrightarrow{AC}=2\overrightarrow{AC}\ne\vec{0}\;\text{False}.$ $(D)\;\overrightarrow{AB}-\overrightarrow{CB}+\overrightarrow{CA} =\overrightarrow{AB}+\overrightarrow{BC}-\overrightarrow{AC}=\vec{0}\;\text{True}.$ $(E)\;\overrightarrow{BA}-\overrightarrow{BC}-\overrightarrow{CA} =-\overrightarrow{AB}-\overrightarrow{BC}+\overrightarrow{AC} =-(\overrightarrow{AB}+\overrightarrow{BC})+\overrightarrow{AC} =-\overrightarrow{AC}+\overrightarrow{AC}=\vec{0}\;\text{True}.$ $\text{Only option (C) is not true.}$ |