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The shortest distance between the two straight lines $\frac{x-4 / 3}{2}=\frac{y+6 / 5}{3}=\frac{z-3 / 2}{4}$ and $\frac{5 y+6}{8}=\frac{2 z-3}{9}=\frac{3 x-4}{5}$ is |
$\sqrt{29}$ 3 0 $6 \sqrt{10}$ |
0 |
Since these two lines are intersecting so shortest distance between the lines will be 0. Hence (3) is the correct answer. |
