A proton and an alpha particle are projected with equal velocities into a perpendicular magnetic field. What will be the ratio of radius of the path traced by them?
Answer & explanation
Correct answer: option 2
Radius $ r = \frac{mv}{qB}$
⇒ r ∝ 1/q
qp : qα = 1 : 2
mα : mp = 4 : 1
rp : rα = qα : qp = 2 : 1