The price of an article increases by 20% every year. If the difference between the price at the end of the third year and fourth year is 259.20, then 40% of the price at the end of the second year ?
Answer & explanation
Correct answer: option 3
20% = \(\frac{1}{5}\) . let original price = 5 ,
increased price = 5 + 1 = 6
I yr II yr III yr IV yr
5 : 6
5 : 6
5 : 6
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overall- 125 : 150 : 180 : 216
( 216R - 180R) = 36R
36R = 259.2 ( given )
1R = 7.2
40% of the price at the end of the second year
\(\frac{2}{5}\) × 150R = 60R
60R = 60 × 7.2 = 432