Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Which of the following functions is a solution to the differential equation as y'+y = 0

Options:

\[y = { e }^{ x } \]

\[y = { e }^{ -x } \]

\[y = { e }^{ -2x } \]

\[y = { e }^{ 2x } \]

Correct Answer:

\[y = { e }^{ -x } \]

Explanation:

$ \frac{dy}{dx} = -y $

$ \int \frac{dy}{y} = -\int{dx}$

$\Rightarrow log_e y = -x $

$ \Rightarrow y = e^{-x}$