The value of $∫\frac{1}{\sqrt{x^2+8x+9}}dx=$ is (Given C constant of integration)
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\log[(x+4)+\sqrt{x^2+8x+9}]+C$
$∫\frac{1}{\sqrt{x^2+8x+9}}dx$
$=∫\frac{1}{(x+4)^2-(\sqrt{7})^2}dx$
$=\log|(x+4)+\sqrt{x^2+8x+9}|+C$