If 7sin2θ + 3cos2θ= 4, 0° < θ < 90°
than the value of (tan2θ + cosec22θ) is?
Answer & explanation
Correct answer: option 3
θ = 30° satisfying the equation.
So, put θ = 30°
(tan2θ + cosec22θ)
= (\(\frac{1}{\sqrt {3}}\))2 + (\(\frac{2}{\sqrt {3}}\))2
\(\frac{1}{3}\) + \(\frac{4}{3}\) = \(\frac{5}{3}\)