If 1.5x = 0.04y, then what will be the value of (y-x)/(y+x) ?

If 1.5x = 0.04y

\(\frac{x}{y}\) = \(\frac{0.04x}{1.5}\) = \(\frac{2}{75}\)

So, the value of $\frac{y-x}{y+x}$ = $\frac{75-2}{75+2}$

So, the value of $\frac{y-x}{y+x}$ = $\frac{73}{77}$