Practicing Success
Practicing Success
CUET Preparation Today
If $\vec a,\vec b,\vec c$ are vectors such that $\vec a.\vec b=0$ and $\vec a+\vec b=\vec c$ then: |
$|\vec a|^2+|\vec b|^2=|\vec c|^2$ $|\vec a|^2=|\vec b|^2+|\vec c|^2$ $|\vec b|^2=|\vec a|^2+|\vec c|^2$ None of these |
$|\vec a|^2+|\vec b|^2=|\vec c|^2$ |
$|\vec a+\vec b|^2=|\vec c|^2$ $|\vec a|^2+|\vec b|^2=|\vec c|^2$ |
