The average of marks of 15 papers is 45. The average of marks of the first 8 papers is 48 and that of the last 8 papers is 40. The marks of the eight paper will be: |
29 28 39 38 |
29 |
The correct answer is Option (1) → 29 Let the marks of the 8th paper be x. Step 1: Total marks of all 15 papers $15 \times 45 = 675$ Step 2: Total marks of first 8 papers $48 \times 48 = 38$ Step 3: Total marks of last 8 papers $8 \times 40 = 320$ The 8th paper is included in both the first 8 and the last 8 papers, so it is counted twice. $\text{First 8} + \text{Last 8} = \text{Total 15} + \text{Marks of 8th paper}$ $384 + 320 = 675 + x$ $704 = 675 + x$ $x = 29$ |