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If f(x) =|x − 2| and g(x) = f(f(x)), then for x > 20, g'(x) is equal to |
–1 1 2 none of these |
1 |
For f(x) = x − 2, x ≥ 2 ⇒ g(x) = f(f(x))= f(x) − 2, f(x) ≥ 2 ⇒ g(x) = x − 4 , x – 2 ≥ 2 ⇒ g(x) = x − 4 , x ≥ 4 ⇒ g'(x) =1 |
