Practicing Success
Two springs P and Q having stiffness constants k1 and k2 (< k1), respectively are stretched equally. Then : |
More work is done on P Their force constants will become equal More work is done on Q Equal work is done on both the springs |
More work is done on P |
Since : \(k_1 > k_2\) Therefore, P will develop greater restoring force than Q. So the applied force on P will be more than the applied force on Q. Extension is same in both the cases. so, more work is done on P. |