If $6tan^2 α - 2 = 0, (0 < α < 90°)$, then the value of α is :

30° 45° 15° 75°

30°

6tan²α - 2 = 0 tanα = \(\frac{1}{√3}\) { we know, tan 30º = \(\frac{1}{√3}\) } So, α = 30º