If $6tan^2 α - 2 = 0, (0 < α < 90°)$, then the value of α is :
Answer & explanation
Correct answer: option 1
6tan²α - 2 = 0
tanα = \(\frac{1}{√3}\)
{ we know, tan 30º = \(\frac{1}{√3}\) }
So, α = 30º
If $6tan^2 α - 2 = 0, (0 < α < 90°)$, then the value of α is :
Correct answer: option 1
6tan²α - 2 = 0
tanα = \(\frac{1}{√3}\)
{ we know, tan 30º = \(\frac{1}{√3}\) }
So, α = 30º