A square loop with each side 1 cm, carrying a current of 10 A, is placed in a magnetic field of 0.2 T. The direction of magnetic field is parallel to the plane of the loop. The torque experienced by the loop is ______.

Fill in the blank with the correct answer from the options given below.

$2 \times 10^{-4} Nm$

The magnetic field is perpendicular to area vector.

$ \tau = NIBA = 10\times 0.2 \times \times 1^{-4} N-m = 2\times 10^{-4} N-m$

The correct answer is Option (2) → $2 \times 10^{-4} Nm$