Practicing Success
Practicing Success
CUET Preparation Today
There are \(n\) persons sitting in a row. Two of them are select at random, the probability that the two selected persons are not together is |
\(\frac{2}{3}\) \(1-\frac{2}{n(n+1)}\) \(\frac{n(n-1)}{(n+1)(n+2)}\) \(1-\frac{2}{n}\) |
\(1-\frac{2}{n}\) |
Required probability \(=\frac{^{n}C_{2}-(n-1)}{^{n}C_{2}}\) |
