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What is the value of $\frac{cos^220°+cos^270°}{sin^290°} - tan^245°$ ? |
0 1 -2 -1 |
0 |
\(\frac{cos²20º + cos²70º}{sin²90º}\)- tan²45º Using , { cos A = sin ( 90º - A ) } = \(\frac{cos²20º + sin²20º}{sin²90º}\)- tan²45º = \(\frac{1}{1}\)- 1 = 0
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