A man goes from A to B at the speed of x km/hr. If he comes back at the speed of y km/hr and takes T hours more than before, then find the distance between A and B.
Answer & explanation
Correct answer: option 1
If distance is equal then time is inversely proportional to speed.
Here,
Ratio of speed = x : y
hence, ratio of time will be = y : x
Distance = Speed × time =x × y = xy
ATQ,
Difference b/w time = x - y = T (given)
⇒ (x - y)R = T
⇒ 1R = \(\frac{T}{x\;-\;y}\)
Distance b/w A and B = xy R = xy × \(\frac{T}{x\;-\;y}\) = \(\frac{xy}{x\;-\;y}\) T