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If tan4x + tan2x = 1, find cos4x + cos2x = ? |
0 1 2 -1 |
1 |
= tan2x (tan2x + 1) = 1 = tan4x . sec2x = 1 ⇒ tan2x = \(\frac{1}{sec^2x}\) = cos2x ⇒ tan2x = cos2x ⇒ sin2x = cos4x Put in find ⇒ cos4x + cos2x sin2x + cos2x = 1 |
