A spider climbed \(37\frac{1}{2}\%\) of the height of a pole in the first hour, and in the next hour it covered 20% of the remaining height. If the pole is 200 m high, what distance did the spider climb in the second hour?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 25 m
The second percentage is taken of the height still left, not of the whole pole. \(37\frac{1}{2}\%=\frac{3}{8}\) and \(20\%=\frac{1}{5}\).
First hour: \(\frac{3}{8}\times200=75\) m
Height left \(=200-75=125\) m
Second hour: \(\frac{1}{5}\times125=25\) m
In the second hour the spider climbed 25 m.