Practicing Success
If the tube length of astronomical telescope is 105 cm and magnifying power is 20 for normal setting, calculate the focal length of the objective |
100 cm 10 cm 20 cm 25 cm |
100 cm |
$L=f_0+f_e$ = 105 cm and M = $\frac{f_0}{f_e}$ = 20 $\Rightarrow f_0$ = 100 cm and $f_e$ = 5 cm |